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• MrSteel01

  Cleveland,Oh
  United States
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  July 16, 2003
  531 Posts
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  Apr 15, 2004, 2:35 pm

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  www.ohiolottery.com

  Well it happened 5/6 times since 5/5/91? 2,500 draws+-

  08-22-23-30-37=120 on 8/14/03 & 10/3/97

  06-20-21-24-36=107 on 10/18/99 & 6/22/93

  04-10-14-21-26=75 on 12/22/98 & 10/3/96

  09-11-18-25-36=99 on 8/21/97 & 2/14/97?

  04-07-11-27-30=79 on 7/4/97 & 6/17/96

  01-20-22-26-29=87 on 12/01/94 & 4/13/93

  Numbers 1 thru 9sums

                              75

                              79

                              87

                              99

                             107

                            120

  Why would after 2,500 draws only those groups/numbers reapeat again!?

   

   

   

   

   
• RJOh

  

  100

  mid-Ohio
  United States
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  March 24, 2001
  20,272 Posts
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  Apr 15, 2004, 3:16 pm

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  Mr Steel,

  Your theory is a fact.  In the Buckeye5 (5/37) game, there are 435,897 possible combinations and 355,167 of them start with numbers 1-10, that 81% of the possible combinations.  Like wise 81% also end with  numbers 26-37.  Only 4,368 combinations(11-25) or 1% of those combinations would not have either of those conditions.

  RJOh

   * you don't need to buy every combination, just the winning ones * 

         
  
• MrSteel01

  Cleveland,Oh
  United States
  Member #1,856
  July 16, 2003
  531 Posts
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  Apr 16, 2004, 10:20 am

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  Quote: Originally posted by RJOh on April 15, 2004
  

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  Mr Steel,

  Your theory is a fact.  In the Buckeye5 (5/37) game, there are 435,897 possible combinations and 355,167 of them start with numbers 1-10, that 81% of the possible combinations.  Like wise 81% also end with  numbers 26-37.  Only 4,368 combinations(11-25) or 1% of those combinations would not have either of those conditions.

  RJOh

  THANK YOU MR ROY!

  
  

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• MrSteel01

  Cleveland,Oh
  United States
  Member #1,856
  July 16, 2003
  531 Posts
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  Apr 16, 2004, 10:43 am

  ▲▼

  Quote: Originally posted by RJOh on April 15, 2004
  

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  Mr Steel,

  Your theory is a fact.  In the Buckeye5 (5/37) game, there are 435,897 possible combinations and 355,167 of them start with numbers 1-10, that 81% of the possible combinations.  Like wise 81% also end with  numbers 26-37.  Only 4,368 combinations(11-25) or 1% of those combinations would not have either of those conditions.

  RJOh

  
  

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  Don't you mean 19 % Roy?
• RJOh

  

  100

  mid-Ohio
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  Apr 16, 2004, 1:01 pm

  ▲▼

  Quote: Originally posted by RJOh on April 15, 2004
  

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  Mr Steel,

  Your theory is a fact.  In the Buckeye5 (5/37) game, there are 435,897 possible combinations and 355,167 of them start with numbers 1-10, that 81% of the possible combinations.  Like wise 81% also end with  numbers 28-37 (the highest ten numbers).  Only 4,368 combinations(11-27) or 1% of those combinations would not have either of those conditions.

  RJOh

  
  

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  Mr Steel there were some mistakes in the original post, those corrections are in blue.  Thanks for bringing it to my attention.

  RJOh

  5/16 or (11-27) possible combinations = 4368 which is 4368/435897 or 1% 

   * you don't need to buy every combination, just the winning ones * 

         
  
• johnph77

  

  CA
  United States
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  December 10, 2003
  832 Posts
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  Apr 16, 2004, 5:59 pm

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  RJOh -

  Is it possible that the number of combinations excluding 01 through 10 and 28 through 37 should read 6188 rather than 4368? Basically, what that does is create a 5/17 lottery draw, of which there are 6188 possibilities. It doesn't significantly alter the substance of youir post, though.....

  gl

  john

  Blessed Saint Leibowitz, keep 'em dreamin' down there..... 

  Next week's convention for Psychics and Prognosticators has been cancelled due to unforeseen circumstances.

   =^.^=
• RJOh

  

  100

  mid-Ohio
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  20,272 Posts
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  Apr 16, 2004, 7:55 pm

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  Thanks john,

  You're right.

  RJOh

   * you don't need to buy every combination, just the winning ones * 

         
  
• johnph77

  

  CA
  United States
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  December 10, 2003
  832 Posts
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  Apr 16, 2004, 9:12 pm

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  If, on the other hand, one chose to restrict one's choices to  those combinations where 1 to 10 comprised the first number and 28 through 37 comprised the last number, there are 280,625 possibilities.

  Blessed Saint Leibowitz, keep 'em dreamin' down there..... 

  Next week's convention for Psychics and Prognosticators has been cancelled due to unforeseen circumstances.

   =^.^=
• RJOh

  

  100

  mid-Ohio
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  March 24, 2001
  20,272 Posts
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  Apr 17, 2004, 3:23 pm

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  280,625/435,897 = 64% of the possible combinations doesn't restrict your choice enough to play all the combinations and trap a winner within those parameters.

  RJOh 

   * you don't need to buy every combination, just the winning ones *