# Using a binomial approach ...

Could you benefit of a binomial approach?

Picking up IGrok's 7 drawings rounds, 5 / 39 Fantasy 5 California.

 FREQUENCY P 0 0.382736755 1 0.393993718 2 0.173820758 3 0.042603127 4 0.006265166 5 0.000552809 6 2.70985E-05 7 5.69296E-07

In a strict sense p = 1/575757.

Curiously 26 numbers had a frequency over 0 with the drawing of 2021-04-23. 26/39=2/3. Those 26 numbers contained the 5 numbers drawn 2021-04-24.

Fantasy 5, California

 2021-04-23 3 11 22 5 10 33 24 25 19 30 34 35 37 23 27 7 20 26 32 12 16 21 14 38 39 F 2 2 2 2 2 2 2 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1

So, I just entered the numbers, applied three or four patterns and used a 2 if 5 coverage.

 3 12 20 27 30 35 3 14 21 23 34 38 7 12 24 27 32 39 7 16 21 25 26 37 11 16 21 23 30 32 14 16 26 27 33 35 19 20 34 37 38 39

Why does your results show 6 numbers ea, for a 5 pick game?

An error. :-D. My standard setting is for pick 6.

Great input Speler.

I convert the Igrok's 7 drawing of the cash 5/36 to root sum. Next, i apply the (=contif) formula to the converted the 7 drawings to root sum to identify how many times each number hit on each column per round.

Applying several patterns and using a 2 if 5 coverage.

 3 14 20 23 35 3 30 32 37 39 5 21 26 30 38 7 10 14 21 37 7 11 12 16 39 7 19 23 30 34 12 25 26 34 37 16 27 32 33 35 24 27 34 38 39

If pick 6/39 you would use 6 drawings per round instead of 7.

39/6=6.5

If you apply Igrok's choice, yes you would?

Whuuut?...

"IF" is right... Whea have YOU seen a 6/39 Game in America?...   ×/39 is barely minimum for a 5 pick Game, with maybe the exception of Fla. at 5/36 I believe...

But most 6 pick Games are between 45-49 Matrix!

You're right Stat\$talker i never seen that. I was just trying to find how many drawings in one round using 39 numbers IF 6 numbers are picked.

Here in Okl. we have 5/36.

39/6
=6.5
1-(1-6/39)^6
=0.6329747044061615033866..

1-(1-6/39)^7
=0.68944013449752..

Thank you Speler.

Welcome Guest

Your last visit: Sun, May 9, 2021, 11:40 pm