Bob
If 00110 was the last game then these are the 5 digit strings.
00110 <-last game
10110
01110
00010 <- play these
00100
00111
The easy way to do this is to write out the previous games pattern 5 times then flip
the digits one at a time starting at the top and moving one place to the right each
line down. This only works when the drawing follows the rule. If I remember correctly
it happens around 1 in every 6 or 7 games on average. If in 30 games there are 5
that follow this rule then, 30*5=$150 ticket cost and 5*$600=$3K for a profit of
$3850.00. This all depends on being able to match the second string of digits. The
first string would require no user analysis as it's static based on the previous draws
values. The second string is not, and this is where some sort of tool or prediction
code would be used.
I find the second string easier to predict but as it is now, it's no sure thing. Lets say
that we allow ourselves 3 different second digit strings, the ticket cost would increase
by a factor of 3 also. $15.00 is my self imposed limit for any lottery bet. Not sure it's
possible but thinking I can tweak the process by maybe adding a few user conditions.
Lets say that analysis indicates at least 3 digits in the second string will repeat from the
previous game. This would cut the total possibilities we have to choose from. Another
thing we could use would be, lets say that we could pin down two of the digits in the second
string which would also reduce the total choices.
Anyway, just another idea, might or might not pan out.
RL