FYI = Went back to check on yesterdays Texas Pick 3 results for Morning-Day using the method I stated in previous post. Here are the results - as usual, pilot-error on my part in adding correctly. Using the exact method described, here are the results - again, Morn draw starts on 0, going R > L and Day draw starts on the 2nd number of 03, the 3, going opposite for next draw ( L > R ).
Texas Pick 3 Morning Result for 03-09-2015 . . . 3-3-3
0+3+1+3| (then 2 added moves) so, starting on 03, zero has no value, so the 3 is added to zero, then once zero is established, 0=1, so 3+0+3+1
0+3+1+3|+5+1 =13, using last number in 13 =3
1+1|+3+2+9+1+3+2+5+1+3+2 = 33 =3
2+(03)+2|+5+1=13 =3 . . . 3-3-3
Texas Pick 3 Day Result for 03-09-2015 . . . 2-5-6
2nd draw, so start on 3 of 03, adding L > R, same rules as before.
03+3|+1+9+2+3+1 = 22 (using last number of 22) = 2 (the underlined numbers show the 3 moves on non-zero numbers until established.)
10*(1)+1|+5+2+3+1+9+2+3+1+5+2 =35 =5 (remember end on 1 or 10, use once to determine moves - not twice and as 1 added).
(2+2)+03|+3+1+9+2+3+1 = 26 =6 . . . 2-5-6
I've found when number ends on the 0 of 03, it is always necessary to add the 03 to the 2+2, or whatever the value of "0" is twice. It works in either direction, as in above and below - I just showed it in different order. Once the zero's are established numbers (not first number), then they have a value and are counted as a regular move. Hey, just working on this - not perfect - but, I'm trying to look in the cracks.
CC