# If you can pick one number you can win P3

There is a Pick-3 system being sold all over the web and on ebay where if you can correctly pick one of the three Pick-3 digits they guarantee you can win Pick-3.  Of course it's just the digit you picked along side the remaining nine digits in all their possible pairings.  Lotto-Logix gives that part of the system away free here: http://www.lotto-logix.com/txthouse/lottodojo2.html

The trouble with the system is you have to get the single digit correct almost every time or you are guaranteed to lose.

What I'd like to know from anyone who has seen one of these systems is what the sellers recommed for picking the one digit that must be correct?  I wrote to one system seller and they claimmed a 70% success rate with no explination.

What's the system(s) for picking the one digit?  Anyone?  Thanks. BobP

I don't know bobp, but that system is risky. I am aware of it by once discovering it when i was analyzing the game. Basically you figure out which 1 digit will likely be drawn. That's all u need. Play all the combinations w/ that 1 digit. It comes out to be 36 all different combinations boxed (251 straight). So basically, it's like having a 1 in 10 chance of winning (for the drawings that doubles/ triples don't hit). It's risky. \$36 to get a 1 in 10 chance + 1 in 3 chance of automatically losing when doubles/ triples hit (boxed play). Just sharing the info that i know. I personally woulnd't use that method of playing. Even if you're good at avoiding the days when double/ triples hit, 1 in ten alone is a risky figure. \$36 to win \$80-\$85 (in most states-boxed play) w/ less than a 1 in 10 chance. I suppose this would be a better simple system to use 4 people who use qwick pick/random/lucky numbers who play 4 fun not expecting to win much. If i were able to predict 1 digit correctly in 8 or 9 times out of ten drawings then i would use the system (it would still be profitably even if the doubles/triples were to hit).

Whoops, sorry bobp. I waystalkin bout a different system fron the 1 u were. I just checked out the site u posted. After actually reading through that site, i will get back to again.

Ok bobp, i read through that site. It actually is the same system that i was referring to. Only difference is that Robert Perkins (is that u by the way?) included doubles and the triple for the 1 key digit chosen on top of the other remaining combos. Do the math of probablity to determine which system is better. If u're good at avoiding double/triple hitting days, try the one i mentioned. If u like to have more winning days, try the one from that site.

"Use the odds against itself"

You can buy the system for \$29.99 or there are eight hours remaining to buy the entire web site system selling business on ebay for \$99.99 which would make good sense if you couldn't buy the system for \$6.95 elsewhere on ebay.

http://cgi.ebay.com/ws/eBayISAPI.dll?ViewItem&category=46687&item=3811281951&rd=1

Don't mention it. ;-) BobP

BobP = perhaps I can shed a little light on this because it is something that I came across 10 years ago when I first started tracking digits.

The 1 digit idea is simply this.....there are exactly 100 combinations with any specific digit in any specific position.  There is also a 60% repeat rate for a digit playing from a previous game.  That's where you look first for the "1" digit to play.  Then figure out what position it will play in, use other criteria to eliminate and reduce the 100 possible combinations down.

Quote:Originally posted by Clipper on April 28, 2004

BobP = perhaps I can shed a little light on this because it is something that I came across 10 years ago when I first started tracking digits.

The 1 digit idea is simply this.....there are exactly 100 combinations with any specific digit in any specific position.  There is also a 60% repeat rate for a digit playing from a previous game.  That's where you look first for the "1" digit to play.  Then figure out what position it will play in, use other criteria to eliminate and reduce the 100 possible combinations down.

Hmmm, it takes 100 combinations to Straight play a digit positionally (in one position) against all the others in their various possible paired positions.  Is that what you meant to say?

There are 36 possible all different combinations with a specific digit in any position.  Three of these collections with the single digit located in each of the three postions would be 108 combinations and still be only box plays.

There are 55 possible  combinations with a specific digit in any position if we include triples, doubles and all different and still only box plays excluding the triple which can only be played straight.  I'm too tired to figure how many combinations this makes moving the selected digit around as doing so wouldn't help anything unless the goal is to have multiple box wins.

For Straight play there are 271 combinations with a selected digit in all three possible positions and the remaining digits in all of theirs.  Obviously ten times 271 is more then 1,000 there is redundency because the same formed combination can be made in more then one set.

Anyhow, none of this helps select the digit to play.  Even if we had 80% draws with one or more repeats, the losses would far exceed the wins.

The system is 100% fool proof once the specific winning digit is selected, if it wins the system must produce a winner when all the combinations are played. What we need is a way to select that winning digit almost every time.

BobP

Exactly Bob.  Clipper, r u sure u know that u're talkin bout. Bobp knows what he's talkin bout.

(u're quote clipper)--->"The 1 digit idea is simply this.....there are exactly 100 combinations with any specific digit in any specific position.  There is also a 60% repeat rate for a digit playing from a previous game.  That's where you look first for the "1" digit to play.  Then figure out what position it will play in, use other criteria to eliminate and reduce the 100 possible combinations down." <- (your statement clipper)

Exactly 100 combinations? Did u forget to calculate the combinations by abiding with the law of thirds. Didn't look like it. You're way off.  Doesn't matter if u're talkin bout boxed combo's, straight, triples, doubles, etc. 100 combinations is incorrect no matter what u apply it to.

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QWEST =Yes...I know what Im talking about.  There are exactly 100 EXACT combinations with any specific digit (0-1-2-3-4-5-6-7-8-9) in any specific position (1st-2nd-3rd).  This means there are 100 EXACT combinations with the 0 in the 1st, with the 1 in the 1st, with the 2 in the 1st, 3, 4, 5, 6, 7, 8 and 9 in the 1st position.

Just as there are 100 EXACT combinations with a digit in the 1st position there are 100 EXACT combinations with each digit in the 2nd position and each digit in the 3rd position.  Each group of 100 contains 3 different digits, Doubles and Triples.

This system is not taking "the one digit" and playing all possible combinations that have "the one digit" but determing which group of EXACTS to use.  Again, the repeat rate generally runs about 60% and that is where you look for "theone" digit to work with.

QWEST = now re-read what I said.....100 EXACT combinations with any specific number in any specific position.

Bobp=I hope I've answered your question as well?  When I first started tracking the Pick 3 I analyzed the 1000 EXACT combinations.

When I tell people they need to have a thorough understanding of the 1000 combinations this is what I am speaking about.  If one has a thorough understanding of the numbers they will realize that each of the 10 digits will appear in 100 EXACT combinations in the 1st, 2nd and 3rd position.  If a Double is involved in will not only be in whatever position you are anticipating, it will also be one of the other positions.  That is immaterial because you are concentrating on the "position' of choice.

Clipper:

Maybe there are 100 combinations with a specific digit in each of the three positions, but isn't that simply redundent boxing as the remaining two digits aren't fixed?  Sorry, I can't get my head around what you're saying, is an example possible?  Visit here, using the 0 as an example where is the system going wrong? Still need ideas how to pick the magical digit. Thanks. BobP

Picking the "magical number" is looking at the most recent game that played in anticipation of a Repeat Digit to go forward to the next game.  Usually it is a 1 in 3 shot unless you are coming off a Doubles game which gives you a 50/50 shot at the "magical  number".

The "redundant boxing" is simply shooting for the EXACT combination to play whereby you rule out the "magical number" from playing in any other position.  This is not for "boxed" game playing.

There are considerations you can make to reduce those 100 exacts down the about 28 or 30 EXACTS and it doesnt matter what the other two digits are.

Quote:Originally posted by Clipper on April 29, 2004

Picking the "magical number" is looking at the most recent game that played in anticipation of a Repeat Digit to go forward to the next game.  Usually it is a 1 in 3 shot unless you are coming off a Doubles game which gives you a 50/50 shot at the "magical  number".

The "redundant boxing" is simply shooting for the EXACT combination to play whereby you rule out the "magical number" from playing in any other position.  This is not for "boxed" game playing.

There are considerations you can make to reduce those 100 exacts down the about 28 or 30 EXACTS and it doesnt matter what the other two digits are.

We're talking about a guaranteed win when one digit is correctly predicted.

There are only two kinds of three digit plays, Box and Straight.  If "Exact" has meaning in Pick-3 I'd take it to mean Straight.  It takes 271 numbers to cover all positions a specific digit can be in with the remaining nine digits in all their possible positions for a guaranteed Straight win when one correctly selects one digit.  Here are the numbers to play if the zero is your chosen digit:

When your selected number is "0" Zero play . . .

A-A-A
0-0-0

A-A-B
0-0-1 0-0-2 0-0-3 0-0-4 0-0-5 0-0-6 0-0-7 0-0-8 0-0-9
A-B-A
0-1-0 0-2-0 0-3-0 0-4-0 0-5-0 0-6-0 0-7-0 0-8-0 0-9-0
B-A-A
1-0-0 2-0-0 3-0-0 4-0-0 5-0-0 6-0-0 7-0-0 8-0-0 9-0-0

A-B-B
0-1-1 0-2-2 0-3-3 0-4-4 0-5-5 0-6-6 0-7-7 0-8-8 0-9-9
B-A-B
1-0-1 2-0-2 3-0-3 4-0-4 5-0-5 6-0-6 7-0-7 8-0-8 9-0-9
B-B-A
1-1-0 2-2-0 3-3-0 4-4-0 5-5-0 6-6-0 7-7-0 8-8-0 9-9-0

A-B-C
0-1-2 0-1-3 0-1-4 0-1-5 0-1-6 0-1-7 0-1-8 0-1-9
0-2-3 0-2-4 0-2-5 0-2-6 0-2-7 0-2-8 0-2-9
0-3-4 0-3-5 0-3-6 0-3-7 0-3-8 0-3-9
0-4-5 0-4-6 0-4-7 0-4-8 0-4-9
0-5-6 0-5-7 0-5-8 0-5-9
0-6-7 0-6-8 0-6-9
0-7-8 0-7-9
0-8-9

A-C-B
0-2-1 0-3-1 0-4-1 0-5-1 0-6-1 0-7-1 0-8-1 0-9-1
0-3-2 0-4-2 0-5-2 0-6-2 0-7-2 0-8-2 0-9-2
0-4-3 0-5-3 0-6-3 0-7-3 0-8-3 0-9-3
0-5-4 0-6-4 0-7-4 0-8-4 0-9-4
0-6-5 0-7-5 0-8-5 0-9-5
0-7-6 0-8-6 0-9-6
0-8-7 0-9-7
0-9-8

B-A-C
1-0-2 1-0-3 1-0-4 1-0-5 1-0-6 1-0-7 1-0-8 1-0-9
2-0-3 2-0-4 2-0-5 2-0-6 2-0-7 2-0-8 2-0-9
3-0-4 3-0-5 3-0-6 3-0-7 3-0-8 3-0-9
4-0-5 4-0-6 4-0-7 4-0-8 4-0-9
5-0-6 5-0-7 5-0-8 5-0-9
6-0-7 6-0-8 6-0-9
7-0-8 7-0-9
8-0-9

C-A-B
2-0-1 3-0-1 4-0-1 5-0-1 6-0-1 7-0-1 8-0-1 9-0-1
3-0-2 4-0-2 5-0-2 6-0-2 7-0-2 8-0-2 9-0-2
4-0-3 5-0-3 6-0-3 7-0-3 8-0-3 9-0-3
5-0-4 6-0-4 7-0-4 8-0-4 9-0-4
6-0-5 7-0-5 8-0-5 9-0-5
7-0-6 8-0-6 9-0-6
8-0-7 9-0-7
9-0-8

B-C-A
1-2-0 1-3-0 1-4-0 1-5-0 1-6-0 1-7-0 1-8-0 1-9-0
2-3-0 2-4-0 2-5-0 2-6-0 2-7-0 2-8-0 2-9-0
3-4-0 3-5-0 3-6-0 3-7-0 3-8-0 3-9-0
4-5-0 4-6-0 4-7-0 4-8-0 4-9-0
5-6-0 5-7-0 5-8-0 5-9-0
6-7-0 6-8-0 6-9-0
7-8-0 7-9-0
8-9-0

C-B-A
2-1-0 3-1-0 4-1-0 5-1-0 6-1-0 7-1-0 8-1-0 9-1-0
3-2-0 4-2-0 5-2-0 6-2-0 7-2-0 8-2-0 9-2-0
4-3-0 5-3-0 6-3-0 7-3-0 8-3-0 9-3-0
5-4-0 6-4-0 7-4-0 8-4-0 9-4-0
6-5-0 7-5-0 8-5-0 9-5-0
7-6-0 8-6-0 9-6-0
8-7-0 9-7-0
9-8-0

If there is a way to reduce these 271 lines to 100 without giving up the GUARANTEE of a STRAIGHT WIN I'd like to see it done. BobP

Exact does mean Straight.....And ...if you do get the "magical number" AND the position it will be in then you ARE guaranteed to win with 100 possible combinations to play.  There are ways to reduce that 100 down to even less by applying the 12 Facts.

Quote:Originally posted by Clipper on April 30, 2004

Exact does mean Straight.....And ...if you do get the "magical number" AND the position it will be in then you ARE guaranteed to win with 100 possible combinations to play.  There are ways to reduce that 100 down to even less by applying the 12 Facts.

Right you are, isn't that what I said eight posts back?  Guess I was confused by your way of saying it would take 300 numbers to play all three positions.

Any ideas for selecting the magical number besides picking one of three or two from the prior draw?  I'd like to make a profit rather then lose two times out of three or worse if I guess wrong every time.

One of the reports selling this system said to use the coldest digit from the last 60 days, just doesn't sound right to me.

BobP

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Did the same thing for Georgia, looks pretty close.

 Georgia Positions 1 2 3 9.94% 9.31% 9.93%

Wow! Thanks Bob.

For Georgia only, The first digit repeats in the first position 9.94 %, it has also repeated in the second position a total of 8.86 %, the first digit has repeated in the third position a total of 7.69 %, for a total repeat percentage of 26.48 %. Surprised me !

I'll check out the other positions later this afternoon if time permits.

Cheers !

Bob

 MISSOURI HAS HAD 4784 DRAWS 4784 # HITS IN NO. 1 POSITION 0 55 1.15% 1 52 1.09% 2 51 1.07% 3 54 1.13% 4 51 1.07% 5 45 0.94% 6 48 1.00% 7 32 0.67% 8 49 1.02% 9 52 1.09% 489 10.22%
Quote:Originally posted by Clipper on May 03, 2004

PS.....besides....I told you earlier I dont have a 1 digit system so it leaves me out.    This discussion was about a 1 digit system and I asked BobP if he had heard about Steve Player's new system and just happened to mention my system and how close I was.  No discussion initiated.

I received Steve's new system advertisement too.  I find it hard to believe a static system can win often enough to play at a profit over time and note he makes no claims of winning, only providing examples of what you would collect if it did win.  I checked a year and a half worth of Florida draw history for the three numbers his example gave 12 pure numbers for, only a hand full of times those three came up and only one win from the handful which I guess made a profit for a handful times \$12.  One really has to wonder whether there is really anything behind it or just a fancy lucky number book like the ones you can buy for a buck at the newspaper stand.

I can see making such a system based on historic followers, would look really good compared against the draw history when back tested, can't say how it would do in future draws.  BobP

Thanks Bluegrass = saves me from having to go back and look at my database lol  Im sure yours is more complete the mine right now because I dont have to keep an extensive database to work my system.

Is interesting indeed to see the % of how often a specific position might repeat itself.  While a digit repeats in same position collectivelyl for all 3 position 42.3% of the time we can now say that anyone specific position does not repeat itself more then 10% of the time.

Clipper, thanks for the effort but something just doesn't seem right.  The question was about the first position and how often it repeats the next day. If 126 hits on Monday then what are the odds the same number will repeat in the first position  on Tuesday as the same number 1 45  etc.?

I had indicated before in the earlier post that it seemed like it might do this about 10% of the time or rather not come back this way 90% of the time. This would allow us to negate at least one of the 10 digit choices for the next day and be right approx. 90% of the time and increase our chances of a straight hit .

Clipper, are you  saying that it does come back in first position more than that? We are talking about First position only right?  My guess would be that using a 7 day a week game that the first digit should not return on top of itself more than 10% of the time. Average. That's because there is just a 1 in 10 chance for any single digit to appear in that 1st. position at any time anyway we cut it. Right?

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Dr P

Yes of course there's a 1 in 10 chance of a digit repeating in the same position. You could also say that there's a 1 in 100 chance that any digit will be drawn in a particular positin and repeat. Let's say that the #3 is drawn in the first positon. The chances of it repeating remains 1 in 10. Let's say that three hasn't been drawn yet and i anticipated it to be drawn twice in a row in the same position. Now the chances of that happening would be 1 in 100. This is all basic math. You don't need to analyze previous drawing to get that answer, however it is a good idea to see the average patterns, and also to see if there's anything out of the norm occurring.

Here is some additional input though about repeat as it pertains to Texas.  I looked at the 211 instances in my database where there had been a repeat digit and looked at the "sequences" of happenings.  In otherwords, how long a sequence did a repeat happen regardless of "where" it repeated.

There was 1 instance of a run of 10 games for repeat with the remainer of the sequences going 6-5-4-3-2-1.  Of course the number of 6 sequence was smaller then 5, 5 smaller then 4 with the higher repeat sequences being between 3-2 & 1.

Of the 3-2-1 sequence runs there were 34 instances where a digit repeated from prior game and the sequence ended.  Of these 34 instances, 17 (50%) of the time when the digit repeated it did so in the same position.    Such happening during a 2-3 sequence run was considerably less...like 3 times out of 16 for 2 sequence and even less for 3 sequence run out of slightly less number of runs.

Quote:Originally posted by QWEST46 on May 04, 2004

_________________

Yes of course there's a 1 in 10 chance of a digit repeating in the same position. You could also say that there's a 1 in 100 chance that any digit will be drawn in a particular posting and repeat. Let's say that the #3 is drawn in the first position. The chances of it repeating remains 1 in 10. Let's say that three hasn't been drawn yet and i anticipated it to be drawn twice in a row in the same position. Now the chances of that happening would be 1 in 100. This is all basic math. You don't need to analyze previous drawing to get that answer, however it is a good idea to see the average patterns, and also to see if there's anything out of the norm occurring.

Quest, thanks for the input. When this thread first began it was about how to pick that Magic"one number"using the 300 positional digits or the 271 representations. Either way, it seemed to be more about how to break these down to fewer play choices. That part of the thread seemed to die out and left the subject hanging out there. This gave a lot of people the impression that we were left with only those 271 or 300 choices. Everyone seemed to be saying that they knew of the system years ago and it wasn't worth anything and had written it off as "not worth it."

I think what Prometheus was attempting to do was point out that although it was also a bad system with only expected win of only 10%, that it was sadly one of the best (known) systems going up till now. He was talking about free open systems that serious players already knew about. I also thought he was attempting to show that most "known systems" can't do much better and was challenging anyone who wanted to help or add anything to jump in.

I did jump in, with what I think is a way to cut down the 300 or 271 choices by at least 1 third over 90% of the time with some "simple basic math."which bluegrass was kind enough to confirm with real world data. This is what I think Prometheus was leading up to, ways to improve on that 10% hit rate. As far as known, open, published systems go, I do not think there is a better system either. Anyway, that's my contribution. That's about a 30% improvement to the way it was left hanging out there. Now, it's a 13%expected hit rate system, 90% of the time. Anyone got one better?

Dr Pepper = I break it down by going with 1 digit/1 position.  Not only do you pick the "magical number" you pick the position it will play in.

Quest46,

I re-read your post and you lost me after you agreed that a digit repeating on top of itself had a 1 in 10 chance of hitting in that same position. That's correct and obvious and confirmed with real world data. But- - - -  then you said, Quote: "You could also say that there's a 1 in 100 chance that any digit will be drawn in a particular posting and repeat."Would you show how this changed from 1 in 10 to the 1 in 100  using some good old basic math to explain. Thanks

Quest46,

I re-read your post and you lost me after you agreed that a digit repeating on top of itself had a 1 in 10 chance of hitting in that same position. That's correct and obvious and confirmed with real world data. But- - - -  then you said, Quote: "You could also say that there's a 1 in 100 chance that any digit will be drawn in a particular posting and repeat."Would you show how this changed from 1 in 10 to the 1 in 100  using some good old basic math to explain. Thanks

Dr. Pepper, Lets say that i play pick three lottery. I choose to play 1 digit exact (some states have 1 digit exact & 2 digit exact). Well anyways i decide to bet on #4 for two days in a row. Now There's a 1 in 100 chance that that digit will be drawn for those 2 days (any particular digit). Now lets say that today #4 was drawn. This would not make the chances of 4 being drawn 1 in 100 tomorrow. The chances of it being drawn tomorrow is still 1 in 10 and always will be. But if you were to say that  4 were to be drawn tomorrow plus the day after that, then the chances of that would be 1 in 100. That's all there is to it. Like i was saying, basic math. All gamblers should know this basic stuff. I'm sure that not everyone here is a gambler. I mean, i wouldn't consider anyone who  just throws out a few bucks on the lottery a gambler. Gamblers are those that expect to win, and when they don't, they find ways to win. Ask anyone about this.

Basically, in the above example, I'm not saying that if the #4 came out today then the chances of it being drawn tomorrow is 1 in 100, it's 1 in ten and will always be 1 in 10. To say that it will come out on two given days, there is a 1 in 100 chance.

Come on, basic math. Coin toss example that everyone (gambler) should know. Head=1 in 2, tails=1 in 2.  ie:

What are the chances of heads landing? >DUH! 1 in 2.

What are the chances of heads landing twice in a row.  (the math, basic)  1/2x1/2=1/4 ONE IN FOUR.

what are the chances of heads landing three times in a row?  1/2x1/2x1/2=1/4= 1 in Eight.

Now if heads were to land two times in a row, the chances of it landing on the next toss is still 1/2 (not 1/8).  The chances of heads landing three times in a row is the 1 in 8 chance.

Do u understand now Dr. Pepper?

If there are 1,000 Pick-3 numbers consisting of three digits each, doesn't that mean there are 3,000 digits in the full set of 1,000 numbers?

Thanks for jumping in Bobp.  Really need the help here. I had no idea where to begin with this and questioned the effort it might involve.

Well, perhaps the attempt might help some other folks at the same time, so any help you could offer would be appreciated. Anything I were to say at this point would sound a little condescending, or too instructive to be of value, and that's not the impression someone wants to give. No one wants to discourage anyone from trying to participate, especially someone who has at least taken the time to master basic probability theory on equally like dvents, (good work) however, sadly misapplied in this case.

Yes bob, there r 3 thousand digits.

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