# Divide and conquer system

Pick 4 selection process

(012) (345) (6789)

2+0+2

1+0+3

3+0+1

0+0+4

4+0+0

2+1+1

1+1+2

0+1+3

3+1+0

1+2+1

0+2+2

2+2+0

0+3+1

1+3+0

0+4+0

15 types

NY Eve last 5 draws

0955-(1+2+1)

1470-(2+1+1)

0187-(2+0+2)

2810-(3+0+1)

4318-(1+2+1)

Wouldn't it be 4 digits +,-  ?

I cant follow, can you provide guidance please?

What do you mean

What part you don’t understand

(012) (345) (6789)

0955-(1+2+1)  =  1 nr 0 from first group of (012) + 2 nr 55 double , from second group (345) + 1 nr 9 from third group (789)

1470-(2+1+1) = 2nr 0 and 1 from group (012) + 1 nr 4 from group (345) + 1 nr 7 from group (789)

Thanks for explaining this idea!

ALL POSSIBLE BOX SINGLES IN 1+2+1

0346
0347
0348
0349
0356
0357
0358
0359
0456
0457
0458
0459
1346
1347
1348
1349
1356
1357
1358
1359
1456
1457
1458
1459
2346
2347
2348
2349
2356
2357
2358
2359
2456
2457
2458
2459

(36)

ALL POSSIBLE BOX DOUBLES IN 1+2+1

0336
0337
0338
0339
0446
0447
0448
0449
0556
0557
0558
0559
1336
1337
1338
1339
1446
1447
1448
1449
1556
1557
1558
1559
2336
2337
2338
2339
2446
2447
2448
2449
2556
2557
2558
2559

(36)

Hey NY10 I finally got it , in your explanation  to Lakerban...I felt like such a dummy before lol!

Thx

Midnite0807

Which process in your opinion produces most hits?

1+2+1 looks good.

Work in progress

ALL POSSIBLE BOX SINGLES IN 1+1+2

0367
0368
0369
0378
0379
0389
0467
0468
0469
0478
0479
0489
0567
0568
0569
0578
0579
0589
1367
1368
1369
1378
1379
1389
1467
1468
1469
1478
1479
1489
1567
1568
1569
1578
1579
1589
2367
2368
2369
2378
2379
2389
2467
2468
2469
2478
2479
2489
2567
2568
2569
2578
2579
2589

(54)

ALL POSSIBLE BOX SINGLES IN 2+0+2

0167
0168
0169
0178
0179
0189
0267
0268
0269
0278
0279
0289
1267
1268
1269
1278
1279
1289

(18)

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