Example

256

Start with the digit 6 change to the mirror, 1.  Put as the third digit.

Next, Add 2+5=7

I put the letter "A" in the first empty position.

A71

Then, 

Calculate the root of the example 256 which is sum 13 Root 4.

A71

  * 4     multiply by the root,

284

Then do a +111 rundown,

284

395

406

517

628

739

840

951

062

173

Nm

851

136

     5

680

680

791

802

913

024

135

246

357

468

579

680

What do you do if you add the first two numbers and ends up being a double digit 10 thru 18 ? Add again until left with one number or do we drop the first number ? example 13 will now be 3 ?

Nevermind, I see now that you kept the double digits and dropped the A.

What happens if after multiplication, the resulting number consists of  4 digits instead of 3. Should we ignore left most or right most digit?

Nm 

611

    76

       8

608

608

719

820

931

042

153

264

375

486

597

608

Then what do we look for Laker Ben? When i looked i noticed when a lot of numbers that came out more than once were winners...is that what we look for?

could this be another Laker Ben Hole in one??

Nm

319

44

44

 *4

176

287

398

409

510

621

732

843

954

065

Neat method. I rarely play more than 1 or 2 lines, but when I do play a lot of lines at once I also do the 111 rundown trick.

973

168

    1   root of 973.

168

279

380

491

502

613

724

835

946

057

Nm

313

48

48

   7

336

447

558

669

770

881

992

003

114

225

Nm

052

57

   7

399

400

511

622

733

844

955

066

177

288

Nm

016

11

7

77

077

188

299

300

411

522

633

744

855

966

Nm

804

     89

       3

  267 

  378

   489

   590

   601

   712

   823

   934

   045

   156