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Pick 4 for ROI

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This thread is based on a simple ideal> Predict just one digit, preferable position 1 for subsequent draw/s  for probably straight hit. The picks are not for the risk averse, but for those who consider waging as residual income, so am not going to indulge in discussion about cost and what not(Every member here is of legal age).

I am open to discuss concepts behind the method of pick selection, give and gather suggestions to enhance this method, I will post picks for validation sake, not on request, is best to learn the ideal and do your own workout.

Method> Predict next position digit +  Np3, N is your data size for certain cycles, p is your Permutation for triads, basically you're grouping all your triads out of N.  The size of N will determine the number of picks to wage.

Hint> 10P4= 5040    , 10P3=720,  predict a number on 10P3 for a straight hit (that's ideal, be mindful that N is not static!)

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In response to adobea78

KY> 5 draws

Bet> straight

Assumption> At LEAST a hit or recover or lose

5012-5013-5014-5015-5016-5017-5018-5019-5010-5011

 

5023-5024-5025-5026-5027-5028-5029-5020-5021-5022

 

5034-5035-5036-5037-5038-5039-5030-5031-5032-5033

 

5045-5046-5047-5048-5049-5040-5041-5042-5043-5044

 

5056-5057-5058-5059-5050-5051-5052-5053-5054-5055

 

5067-5068-5069-5060-5061-5062-5063-5064-5065-5066

 

5078-5079-5070-5071-5072-5073-5074-5075-5076-5077

 

5089-5080-5081-5082-5083-5084-5085-5086-5087-5088

 

5090-5091-5092-5093-5094-5095-5096-5097-5098-5099

 

5123-5124-5125-5126-5127-5128-5192-5120-5121-5122

 

5134-5135-5136-5137-5138-5139-5130-5131-5132-5133

 

5145-5146-5147-5148-5149-5140-5141-5142-5143-5144

 

5156-5157-5158-5159-5150-5151-5152-5153-5154-5155

 

5167-5168-5169-5160-5161-5162-5163-5164-5165-5166

 

5178-5179-5170-5171-5172-5173-5174-5175-5176-5177

 

5189-5180-5181-5182-5183-5184-5185-5186-5187-5188

 

5190-5191-5192-5193-5194-5195-5196-5197-5198-5199

 

5345-5346-5347-5348-5349-5340-5341-5342-5343-5344

 

5356-5357-5358-5359-5350-5351-5352-5353-5354-5355

 

5234-5235-5236-5237-5238-5239-5230-5231-5232-5233

 

5245-5246-5247-5248-5249-5240-5241-5242-5243-5244

 

5256-5257-5258-5259-5250-5251-5252-5253-5254-5255

 

5267-5268-5269-5260-5261-5262-5263-5264-5265-5266

 

5278-5279-5270-5271-5272-5273-5274-5275-5276-5277

 

5289-5280-5281-5282-5283-5284-5285-5286-5287-5288

 

5290-5291-5292-5293-5294-5295-5296-5297-5298-5299

 

5378-5379-5370-5371-5372-5373-5374-5375-5376-5377

 

5390-5391-5392-5393-5394-5395-5396-5397-5398-5399


5456-5457-5458-5459-5450-5451-5452-5453-5454-5455

 

5467-5468-5469-5460-5461-5462-5463-5464-5465-5466

 

5478-5479-5470-5471-5472-5473-5474-5475-5476-5477

 

5489-5480-5481-5482-5483-5484-5485-5486-5487-5488

 

5567-5568-5569-5560-5561-5562-5563-5564-5565-5566

 

5578-5579-5570-5571-5572-5573-5574-5575-5576-5577

 

5589-5580-5581-5582-5583-5584-5585-5586-5587-5588

 

5590-5591-5592-5593-5594-5595-5596-5597-5598-5599

 

5678-5679-5670-5671-5672-5673-5674-5675-5676-5677

 

5689-5680-5681-5682-5683-5684-5685-5686-5687-5688

 

5690-5691-5692-5693-5694-5695-5696-5697-5698-5699

 

5789-5780-5781-5782-5783-5784-5785-5786-5787-5788

 

5790-5791-5792-5793-5794-5795-5796-5797-5798-5799

 

5890-5891-5892-5893-5894-5895-5896-5897-5898-5899

 

5901-5902-5903-5904-5905-5906-5907-5908-5909-5900

 

mrlotto-nc's avatar - Sphere animated2.gif
In response to adobea78

Adobea,

 

Not too familiar with Pick4 so have a question.

This leading digit chart contains all the permutations of the 3 remaining digits behing the leading digit?

 

If so, do you have the charts for the other key digits 0-9?

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In response to mrlotto-nc

I get your drive, but am not going to give that chart out.  I'll prefer to share the ideal , which is clearly stated than  a finish 'product'. I had a situation some months ago of someone peddling my file on the net, at this juncture, is best to discuss concepts.

NB> you can deduced the triads from the picks just posted, but N is not static.

mrlotto-nc's avatar - Sphere animated2.gif
In response to adobea78

Ok cool. Yeah this idea isnt bad, but not for the faint at heart. But not a bad idea at all buddy.

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In response to mrlotto-nc

The reason I said not for the 'risk averse', it pays off big time if consider it as return on investment. Look at the P3 thread that was locked yesterday, most picks were straight hits within 2 draws for huge returns, is all about choice-my strategy is straight bet or nothing, win or lose, there no middle ground.

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In response to adobea78

Method> Pos 1 +Np3

Hint> Keep the size of N to 5 or 6 string length, ie 01254, 724013 and reduce triads to simple permutation without repeat.    6P3>120triads,    6P3>216 (with repeat digit)

Method> pos 1 +120triads  or Position 1 +216 triads  for straight hit within a short span

Task> Generate your string for N,  members of N are not fixed.

Pheonix57's avatar - Lottery-062.jpg
In response to adobea78

You are truly good with these number systems.I have been thinking about this concept for a couple of days, and it has merit.

I don't know if I can explain what I am thinking, but here goes....

N = first digit (we need a method/workout to determine this)

I have been looking at BlackApple's thread regarding the first digit.  He shows how one can use Vtrac short sums to narrow the field of numbers from 10 (0-9) to 4 (1-2-5-7, 3-8-4-9, etc) based on last 4 draws. 

Vtracs 1(5-0), 2 (1-6), 3 (2-7), 4 (3-8), 5 (4-9)

From these remaining digits, one could reduce digits further to 2 digits by determining which of the 4 digits are the longest out. Now we have only 2 digits to choose from, giving a 50/50 chance of success.

This was one method I thought about.

The next idea was using Dr Miracle's number followers:

3-5-8

1-4-6-0

2-7-9

These numbers tend to follow each other.  I have seen it work as a single digit or sum.

Btw, I am still a little confused on the string concept.  Based on the number list published, I do understand the sequence. I just don't understand how to represent it as a string.  I am thinking that the string is based on the digits not drawn in the last x draws?.

N =first digit

N012.....N019  (horizontal flow - first 3 digits constant, last digit changes through 9)

N023.....N029 (vertical flow - first & second digit constant, third and fourth digit = +1 of previous digit, continue through 9)

Please share your thoughts.

P57

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In response to Pheonix57

Is just a simple proposition that come with cost, most people want to win, but how badly do you need this win? If you can device a predictive method with 50% degree of certainty, then COST becomes investment.

P4 has 10,000 combinations  for straight hit for net lost of $5000

Waging 5040 straight combo is still a lost

Single box combinations of 210 picks is also lost by default.

Now take a look at All triads of P4 without a digit repeating>10!/7! (720 picks), so all it takes to predict 1 or 2 digits for next five draws for a straight hit.

Take any State draws, eg Tx

Drawing DatePick 3Pick 4
MiddayEveningMiddayEvening
Wed, Nov 26, 20140-7-90-9-4-5
Tue, Nov 25, 20148-1-5
0-2-0
7-5-6
4-1-4
3-3-1-3
6-1-2-8
7-8-9-9
1-4-7-4
Mon, Nov 24, 20142-5-9
2-4-3
8-0-2
8-3-3
1-6-5-2
3-2-6-5
3-6-7-6
4-6-2-6
Sat, Nov 22, 20142-9-1
4-7-7
9-4-0
0-3-0
5-5-4-3
2-2-0-1
1-7-6-1
1-7-0-2
Fri, Nov 21, 20141-2-0
9-7-7
3-1-2
6-6-8
6-1-0-7
0-2-6-6
8-2-3-9
6-4-1-3
Thu, Nov 20, 20143-7-4
5-1-8
4-9-0
1-1-7
8-6-5-6
8-6-4-6
6-6-1-6
4-0-2-8
Wed, Nov 19, 20144-2-0
5-2-9
5-7-2
8-6-7
7-0-6-9
6-0-0-6
8-3-4-7
6-8-2-9
Tue, Nov 18, 20144-8-5
8-1-6
1-6-6
3-1-6
4-8-9-2
3-0-7-3
3-0-4-7
2-0-2-4
Mon, Nov 17, 20147-9-4
7-3-9
0-9-3
6-7-1
8-9-2-6
1-4-2-5
3-6-0-5
4-9-1-0
Sat, Nov 15, 20147-3-0
9-3-2
8-1-9
8-2-7
3-7-0-9
8-8-7-2
3-4-0-1
7-9-6-3

draw   7963 will give me two key digits 2,4 for position + 720 triads at cost of 1440(do not be scared if certainty is over 50%). You had str hits 2024, 4028 , is it cost effective? depend on waging strategy(waging combined or a type draw). Draw 8892> key 0,5  for str hits ,5543(Betting is Morn/day draws) 

Draw>3401> key 8,1 for str hit 8347, 8239,1702,1761

Inference> The propensity of hits confirms the degree of certainty, is it profitable? you decide.

Now the 720 triads is too much or you feel uncomfortable , then step down with simple 10C3> 120 triads

120 triads

draw        key                 hits

8872         0,5               box 3709,7069>>> check cost for box hits

7963        2,4                str 2024, 4028>> check cost for str hits

3401         8,1              str 8347,  8239, Box 1702,1761> check cost for str hit within such time frame.

Why not find a middle ground between 720/120 triads by considering 10P3 with a digit repeat for 220 triads, predict a key digit for potential straight.

Reducing the size of N based on current draw:

This is locating a group (string) based on current draw and setting up Np3, it can be done by setting parameters,eg, sums for prediction points, the number points becomes the size of N. So for a draw 8872,

my points will be 0.2,1,3,5,7   for N=6, my triads will be 6P3(120 triads) or 56 triads with one repeat digit.

NB> I suggest, you leave the string part and focus on predicting your key digits with 220 triads. You can check the net for permutation table, LP has it.

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In response to adobea78

Strategy> 10P3 with one repeat for 2 key digits, strictly straight for 5 draws

 

Assumption> At LEAST a hit, recover cost or lost , based on 50% degree of certainty

 

Potential Prize> $5000 + within time frame

 

 

GA>key 4,8

 

4123-4124-4125-4126-4127-4128-4192-4120-4121-4122

4134-4135-4136-4137-4138-4139-4130-4131-4132-4133

4145-4146-4147-4148-4149-4140-4141-4142-4143-4144

4156-4157-4158-4159-4150-4151-4152-4153-4154-4155

4167-4168-4169-4160-4161-4162-4163-4164-4165-4166

4178-4179-4170-4171-4172-4173-4174-4175-4176-4177

4189-4180-4181-4182-4183-4184-4185-4186-4187-4188

4190-4191-4192-4193-4194-4195-4196-4197-4198-4199

 

 

4345-4346-4347-4348-4349-4340-4341-4342-4343-4344

4356-4357-4358-4359-4350-4351-4352-4353-4354-4355

4367-4368-4369-4360-4361-4362-4363-4364-4365-4366

4378-4379-4370-4371-4372-4373-4374-4375-4376-4377

4389-4380-4381-4382-4383-4384-4385-4386-4387-4388

4390-4391-4392-4393-4394-4395-4396-4397-4398-4399

 

 

4678-4679-4670-4671-4672-4673-4674-4675-4676-4677

4689-4680-4681-4682-4683-4684-4685-4686-4687-4688

4690-4691-4692-4693-4694-4695-4696-4697-4698-4699

 

4901-4902-4903-4904-4905-4906-4907-4908-4909-4900


8123-8124-8125-8126-8127-8128-8192-8120-8121-8122

8134-8135-8136-8137-8138-8139-8130-8131-8132-8133

8145-8146-8147-8148-8149-8140-8141-8142-8143-8144

8156-8157-8158-8159-8150-8151-8152-8153-8154-8155

8167-8168-8169-8160-8161-8162-8163-8164-8165-8166

8178-8179-8170-8171-8172-8173-8174-8175-8176-8177

8189-8180-8181-8182-8183-8184-8185-8186-8187-8188

8190-8191-8192-8193-8194-8195-8196-8197-8198-8199

 

8345-8346-8347-8348-8349-8340-8341-8342-8343-8344

8356-8357-8358-8359-8350-8351-8352-8353-8354-8355

8367-8368-8369-8360-8361-8362-8363-8364-8365-8366

8378-8379-8370-8371-8372-8373-8374-8375-8376-8377

8389-8380-8381-8382-8383-8384-8385-8386-8387-8388

8390-8391-8392-8393-8394-8395-8396-8397-8398-8399

 

 

8678-8679-8670-8671-8672-8673-8674-8675-8676-8677

8689-8680-8681-8682-8683-8684-8685-8686-8687-8688

8690-8691-8692-8693-8694-8695-8696-8697-8698-8699

8901-8902-8903-8904-8905-8906-8907-8908-8909-8900






 






 

 

 

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In response to adobea78

MASS> 5 draws for str bets

7012-7013-7014-7015-7016-7017-7018-7019-7010-7011

7023-7024-7025-7026-7027-7028-7029-7020-7021-7022

7034-7035-7036-7037-7038-7039-7030-7031-7032-7033

7045-7046-7047-7048-7049-7040-7041-7042-7043-7044

7056-7057-7058-7059-7050-7051-7052-7053-7054-7055

7067-7068-7069-7060-7061-7062-7063-7064-7065-7066

7078-7079-7070-7071-7072-7073-7074-7075-7076-7077

7089-7080-7081-7082-7083-7084-7085-7086-7087-7088

7090-7091-7092-7093-7094-7095-7096-7097-7098-7099

 

 

 

1012-1013-1014-1015-1016-1017-1018-1019-1010-1011

1023-1024-1025-1026-1027-1028-1029-1020-1021-1022

1034-1035-1036-1037-1038-1039-1030-1031-1032-1033

1045-1046-1047-1048-1049-1040-1041-1042-1043-1044

1056-1057-1058-1059-1050-1051-1052-1053-1054-1055

1067-1068-1069-1060-1061-1062-1063-1064-1065-1066

1078-1079-1070-1071-1072-1073-1074-1075-1076-1077

1089-1080-1081-1082-1083-1084-1085-1086-1087-1088

1090-1091-1092-1093-1094-1095-1096-1097-1098-1099

 

 

 

7345-7346-7347-7348-7349-7340-7341-7342-7343-7344

7356-7357-7358-7359-7350-7351-7352-7353-7354-7355

7367-7368-7369-7360-7361-7362-7363-7364-7365-7366

7378-7379-7370-7371-7372-7373-7374-7375-7376-7377

7389-7380-7381-7382-7383-7384-7385-7386-7387-7388

7390-7391-7392-7393-7394-7395-7396-7397-7398-7399

 

 

1345-1346-1347-1348-1349-1340-1341-1342-1343-1344

1356-1357-1358-1359-1350-1351-1352-1353-1354-1355

1367-1368-1369-1360-1361-1362-1363-1364-1365-1366

1378-1379-1370-1371-1372-1373-1374-1375-1376-1377

1389-1380-1381-1382-1383-1384-1385-1386-1387-1388

1390-1391-1392-1393-1394-1395-1396-1397-1398-1399

 

 

 

7567-7568-7569-7560-7561-7562-7563-7564-7565-7566

7578-7579-7570-7571-7572-7573-7574-7575-7576-7577

7589-7580-7581-7582-7583-7584-7585-7586-7587-7588

7590-7591-7592-7593-7594-7595-7596-7597-7598-7599

 

 

 

1567-1568-1569-1560-1561-1562-1563-1564-1565-1566

1578-1579-1570-1571-1572-1573-1574-1575-1576-1577

1589-1580-1581-1582-1583-1584-1585-1586-1587-1588

1590-1591-1592-1593-1594-1595-1596-1597-1598-1599

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what do u see for nc tonite adobea78

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In response to adobea78

For folks with limited budget, use the concept of recurrence or sequential difference to establish the size of N, hence NP3 for your triads, this will reduced your picks to just 24 picks. The two concepts  basically gives  a range of prediction points(prediction interval). Say, my draw is 1234, recurring points will be 8197 for 4P3 triads, the points 8,1,9,7 has size 4 (4 elements) for 24 triads >>>>>>>>>>>>>>>>>>>>>>>>>>

{8,1,9} {8,1,7} {8,9,1} {8,9,7} {8,7,1} {8,7,9} {1,8,9} {1,8,7} {1,9,8} {1,9,7} {1,7,8} {1,7,9} {9,8,1} {9,8,7} {9,1,8} {9,1,7} {9,7,8} {9,7,1} {7,8,1} {7,8,9} {7,1,8} {7,1,9} {7,9,8} {7,9,1

Predict next position 1 digit/s and add it to your 24 triads, you can also consider 4P3 with one repeat digit for 64 triads 

NB> The two concepts has been exhausted in most of my threads, even with charts, so I will not repeat again.

Pheonix57's avatar - Lottery-062.jpg
In response to adobea78

Adobea78,

I have been reading this thread over and over and over, and reading some of your previous threads that are my favorites, and I think I have it now.  I will refer to a previous example that you gave. I believe this is what you are referring to, but in this thread, you are going at a differently, but with the same end result.

Take any State draws, eg Tx

Drawing DatePick 3Pick 4
MiddayEveningMiddayEvening
Wed, Nov 26, 20140-7-90-9-4-5
Tue, Nov 25, 20148-1-5
0-2-0
7-5-6
4-1-4
3-3-1-3
6-1-2-8
7-8-9-9
1-4-7-4
Mon, Nov 24, 20142-5-9
2-4-3
8-0-2
8-3-3
1-6-5-2
3-2-6-5
3-6-7-6
4-6-2-6
Sat, Nov 22, 20142-9-1
4-7-7
9-4-0
0-3-0
5-5-4-3
2-2-0-1
1-7-6-1
1-7-0-2
Fri, Nov 21, 20141-2-0
9-7-7
3-1-2
6-6-8
6-1-0-7
0-2-6-6
8-2-3-9
6-4-1-3
Thu, Nov 20, 20143-7-4
5-1-8
4-9-0
1-1-7
8-6-5-6
8-6-4-6
6-6-1-6
4-0-2-8
Wed, Nov 19, 20144-2-0
5-2-9
5-7-2
8-6-7
7-0-6-9
6-0-0-6
8-3-4-7
6-8-2-9
Tue, Nov 18, 20144-8-5
8-1-6
1-6-6
3-1-6
4-8-9-2
3-0-7-3
3-0-4-7
2-0-2-4
Mon, Nov 17, 20147-9-4
7-3-9
0-9-3
6-7-1
8-9-2-6
1-4-2-5
3-6-0-5
4-9-1-0
Sat, Nov 15, 20147-3-0
9-3-2
8-1-9
8-2-7
3-7-0-9
8-8-7-2
3-4-0-1
7-9-6-3

Let's take draw 8872 (sum=25,rt=7).

Based on one of your previous charts, this draw (8872) brings sets 2489:9670.  Since the draw contains pair 28 from set 2489, our concentration should be on set 9670.  From set 9670, we get triads 967x,960x,970x, and 670x. For x, we could choose digits not within the range 0-9 that have not been drawn. Range: (0,1,2,3,4,5,6,7,8,9)

So our 20 Picks would be 9670,9671,9673,9675,9676,9600,9601,9603,9606,9605,9700,9701,9703,9706,9705,6700,6701,6703,6706,

6705. Now these picks are for box plays only. For straight plays, these would need to be played 12 (6)/24 (14) ways for 408 picks.

Now these picks could be reduced by focusing on the first triad 967x; 5 picks boxed, 108 picks straight. Straight hit with draw 7963.

Please advise if this is correct.

I am still confused about the key digits though.

P57

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In response to Pheonix57

Use the sum parameters for your workout, while you study this permutation method, this method does not come cheap, though the reward is huge, you have to have confidence and knowledge of the method.

See the draw 8827 with keys 2489, 9670, since the digits of the key sets are positional, start filtering/deleting digits 8827 from key sets but maintain the structure> x4x9 and 96x0>>94x9, 96x0,96x9, now fill in x starting with the draw digits 8,2,7 etc

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