# Reducing number pool size without eliminating winning numbers

The most important thing a player can do to win a lottery is play the winning numbers but playing all the possible numbers make that almost impossible with an affordable amount of combinations.  To solve that problem players reduce the number pool size but risk removing the winning numbers.

One of the best way I've found to do this is to limit the pool size to limit number selection to a fixed amount of previous drawings.  You will not only have a smaller pool of numbers but 80% of the time will have at least three of the winning numbers and all the winning numbers about 10% of the time.  Best of all these numbers can be covered in 10 lines or less with good number management that avoid repeating past winners.

This applies to pick3/pick4 as well

" The most important thing a player can do to win a lottery is play the winning numbers"...well that's a no brainer....however how does one go about knowing beforehand  what the " winning numbers are? That's the kind of information players want to get their hands on RJOH.

Also, regarding that part of having (3) of the winning numbers 80% of the time, this must occur with those (3) numbers all on the same line for it to be an "intended'  consistent and dependable approach. Otherwise, QP's can net (3) scattered but matching numbers as I've done that many times in the past. Not saying it cannot be done, just that such consistency will define the approach as intended... as opposed to luck.

L.L.

"these numbers can be covered in 10 lines or less"

You can have a very good chance of having 3 of 5 or 6 winning numbers by playing 60 or 50% of the possible numbers. For a 6/54 game you can do that with 5 or 6 lines. 9 lines can guarantee them all 100% of the time, because you can use all 54 available numbers.

None of that does anything to improve your chances. Not only do you need to play enough of the winning numbers, yu need to play them on the same line. You may think that having 4 of 6 winning numbers in 4 or 5 lines means you've come closer than missing them all, but you haven't. There are exactly two possibilities. You can win or you can lose, and they're both like being pregnant - you can't lose just a little bit.

Playing all 54 numbers on 9 lines is something I do often. It guarantees having all the winning numbers. Then it's up to luck for any of them to fall on the same line.

I'll usually have one line with 2 winning numbers, occasionally 3 winning numbers.

Actually, the best I've done this year is when I played 12 numbers on 2 lines. I had 4 winning numbers on 1 line and 2 on the other.

That's true for my state's 6/49 game as well.  Maybe I should be looking at the mixing patterns and play all the numbers in 9 lines know that all the winning numbers are there and it's just a matter of getting the right mix of six.

Like the fact that it's ten lines or less.

In his second paragraph he explains a possible remedy.

One of the best way I've found to do this is to limit the pool size to limit number selection to a fixed amount of previous drawings.  You will not only have a smaller pool of numbers but 80% of the time will have at least three of the winning numbers and all the winning numbers about 10% of the time.  Best of all these numbers can be covered in 10 lines or less with good number management that avoid repeating past winners.

If you want to play all the numbers but also limit the pool size BobP had an idea, and I use it also. Basically eliminate the 6 numbers that were drawn in the last drawing. Obviously there will be a repeat occasionally, but many times there will not be a repeat. This eliminates millions of combinations. Also, for me, I will leave out numbers 50-54 along with the last 6 drawn, leaving 43 numbers to play. When those conditions are met, the odds go from 1 in 25,827,165 to 1 in 6,096,454. That's over 19 million combinations off the table.

And how many draws back do you suggest to wheel?  What kind of wheel and how many numbers?

The most important thing a player can do to win a lottery is:

For a 6/49 game, you can catch a winner 72% of the time by just playing the numbers from the last 4 games.

31% = 3 match

28% = 4 match

11% = 5 match

2%  = 6 match

This reduces the field of 49 down to about 26 numbers, or just over half the possibilities,  which is still a lot to wheel.

Assuming a similar reduction for the PB you would end up with 32 numbers, or for MM, 40 numbers.

That must vary by state.  I looked at the 1226 drawings of Ohio's Classic Lotto(6/49) and it was 47.9%

Of the 1226 combinations, 1208 had all 6 numbers in the previous drawings and when only looking at the previous 4 drawings the results were at follows:

match 6 =2       0.1%
match 5 =36     2.9%
match 4 =152  12.5%
match 3 =392  32.4%
total      =582  47.9%

match 2 =396 32.7%
match 1 =190 15.7%
match 0 =40    3.3%

Ah!  I should have mentioned that the bonus number is included -- so really only the 4 match and up would win any money.

Welcome Guest

Your last visit: Sun, Sep 26, 2021, 10:48 am