  # Pulling out Pairs Does any one have a method or formula to pull out pairs.

say from a choice of 3

if previous number drawn was say 802.

what can we use to pull pairs out from that number
and limit it to 3 pairs? working with the previous drawn number and always changing any 0's to 5's  in that number set it up like this...

WC"s

435=    3

and see how the pairs come out.

From this the "81" pair could have been gotten to give you

next number 801

Taking 801 changing to 851

5

841...the 51 pair  gives you 151 next number

151.....

5

141...the 93 pair gives you 931

931...

3

921...the 82 pair gives you 802

802...change to 852

5

842...gives 94 pair gives you 794

now take 794

9

Sometimes the simpliest is the best...

mysticwomyn working with the previous drawn number and always changing any 0's to 5's  in that number set it up like this...

WC"s

435=    3

and see how the pairs come out.

From this the "81" pair could have been gotten to give you

next number 801

Taking 801 changing to 851

5

841...the 51 pair  gives you 151 next number

151.....

5

141...the 93 pair gives you 931

931...

3

921...the 82 pair gives you 802

802...change to 852

5

842...gives 94 pair gives you 794

now take 794

9

Sometimes the simpliest is the best...

mysticwomyn

more detail please - just don't get it how you arrive at numbers. me too....how she from 435...............come up with pair 81   me too....how she from 435...............come up with pair 81

435=    3

and see how the pairs come out.

From this the "81" pair could have been gotten to give you

I believe she  Added 3 to 5 to get 8

and took 2 from 3 to get 1 thanks tntea 5

841...the 51 pair  gives you 151 next number

Not sure how she got  51 from this workout.. Why not just take  the pairs from 802...........80,82,02....you will get more hits that way rather than some formula. you mix and you use actual numbers

you set your drawn number up like this

X

X    X  these never change unless one of the numbers is a 0..then make it a 5...801 and 802 are changed to 851 and 852

The number in the center is always one less than the one on top.

3

4  2 5...81 comes from (3+5=8) & (3-2=1)...so that's one pair.  The question was to pull out three pairs...then you could use actual numbers for your next pair..also if you see 3 numbers adding up to 10 use the 10 pair

and in this example (3+2+5=10) 81-10=801

I could go on and explain every one but I think you can understand now.

The last example

9

7 8 4...uses the actual number pair 78 and (9-7=2 plus the actual 8=28)

78-28=278 last nite.

Backtest about 20 numbers and see where they come from..you'll get the hang of it. ok.. say the number was 979

7

9  6  9

From here we get?  29 pair  26 pair 19 pair 12 pair ...........so forth..

How would you know which to use? if you can get the same result twice there's a pretty good chance that

7

9 6 9

from this I see how you could get "2" twice

(9-7=2)  (9-7=2)

and also "3"

(9-6=3)  (9-6=3)

So "23" would surely be one of your pairs.

Since there are two "9's" in the workout...that also would be in one of you pairs.

There's no way to tell which one to use...the original question was how to pull three pairs out.  This is an easy way...you just have to see if it works for your state.