Instead of a 1 n 10 chance.......Do ya want to find a way to have a 1 n 3 chance at getting thefirst digit correct digit in Pick 3? How about a 1n3 chance at at the right Sum instead of 1 n 10 ? Increase our chances ...... yes. Very much.
Find the 10 short sums chart and then find an instance where 3 of the 10 are all missing at the same time. Important (All 3 must be missing for at least 15 draws) Together.
Example: Short sums 0,,,,,,1,,,,,,, and 2 are all missing at the same time. The 0 has been missing for 43 days. The digit 1 for 23 days. The digit 0 for 15 days. All in first position only.
Now ..... since these are "Short Sums" we must divide each by 3 sooooo......
43/3= 14.33 23/3=7.6 and last digit 0 for 15/3=5
Now instead of 43 days ...its 14 draws out. Instead of 23 its 7 days out ...... and its not 15 days it's 5 days out. Divide by three ...and its equal to or the same as all 3 digits missing in all positions for that length of time.
As long as the shortest missing digit /sum has been out for at least 15 days or 15/3 = 5 normal days. It will work.
First Position
Almost the same thing is involved for a 1 n 3 chance at first position odds . Beats 1 n 10 right?
Ex. Digits 4,,,,,5,,,,and 6 are all missing at the same time from position one. The digit 4 has been missing for 52 days .... the digit 5 for 24 days ....and the digit 6 for 16 days.
Since this is for a single position and not ALL POSITIONS missing digits then we must divide by 3 AGAIN. So 52/3= 17 24/3=8 and the last digit missing 16/3= 5.3
ODDS are very high that the next draw will come from one of these 3 missing digits once all three have crossed over the line. When the least of the 3 digits has been missing for at least 15 draws.
" They can hide one of something forever and 2 of something almost as long....but they just can't hide 3 of something very long at all"
hi trying to follow your key 3. where is the 10 short sums chart you refer to?secondly are these 2 separate issues you mean/ using sums to figure the plays or just positions. A little confused. need help. thanks
Yes Win D you really nead to explain this more clearly for us to follow.
Raziel
Your right. Let's try this. First... if anyone can print out one of my old " 10 column Short Sums Charts " i would appreciate it. I can't make it print out anymore. It times out on me.
Missing digits ... All positions ( Finding digits that are missing for at least 5 or 6 days) minimum.
1. If you find 3 digits missing at the same time in All positions for at least 5 or 6 draws.... well,,,, (without going into the math of it right now) ...it's almost a Lock that one of the 3 digits will hit in the very next draw. This is a very strong indicator. This is sooo strong that we can say it .."Most of the time". Anything in this game you can say that about is a "Keeper. " You can build on those. Very much.
2. Short sums. When you find 3 sums(short sums) missing at the same time it works just as well. The only difference is that you must figure missing sums at a different rate. If,, for example ,,,,a sum 8 is missing for 23 days ...you must divide by 3. This way you can picture it in the same way you did above. This way ...23/3 = 7.6 days or normal days skipped . Now... this gives you a better feel for how tardy that missing sum really is. It's kinda like a missing digit thats missing in all positions for 7 days. Thats all.
There are only 12 six way numbers under each short sum to consider.
3. Lastly. By single position . If you want to cut the odds down when you are trying to figure what digit is going to come in firstposition try this. Same as Short Sums above. This cuts your odds down from guessing between 110 digits .....and 13 digits. Three's better odds right? Anytime you can cut your odds down by 66% it's a pretty darn good.
When you want to figure ONE Position only ......take the total number of missing days that it missed and divide by 3. If its missed 43 days in a row you divide by 3...... and this gives you 14.3 normal days missing. This is just like a normal digit missing in ALL positions for 14 days. People understand the idea of 14 missing draws better than 43 ....... who can relate to that big of a number? Not me.
OK...... forget having to divide and all that. If you want to figure which one of three short sums is going to show in the next draw or two at very high probability do this. Just count the days that each of the 3 missing Sums is out.
Like this ...... Sum 4 missing 18 days
Sum 6 missing 37 days
Sum 9 missing 48 days
For this to work ....... you must wait until the smallest amount of time that one of the 3 Missing Sums is out is at the least ........ 15 to 18 days. This way you don't have to divide by 3. The divide by 3 thing is just to give you a better feel of how truly late or missing these sums really are.
* Remember...... one of the 3 missing sums will show. Not necessarily the one missing the longest amount of time.
Win d's Short Sum Chart....... and 4 Quarters
A 




 B 

 

 0  1  2  3  4 
 5  6  7  8  9 
 1  037  029  039  049  013 
 014  015  016  017  018 
1>  2  127  038  057  058  059 
 023  079  025  035  027 
 3  136  047  129  067  149 
 069  169  034  125  036 
 4  145  056  138  148  158 
 078  178  124  134  045 
2>  5  235  128  147  238  167 
 168  259  269  189  126 
 6  389  146  156  247  239 
 249  349  278  279  289 



 C 




 D 


 7  479  236  237  256  257 
 258  358  368  369  469 
3>  8  569  245  589  346  347 
 267  367  458  378  478 
 9  578  489  679  689  356 
 348  457  467  459  568 
 10  019  678  345  012  789 
 456  123  089  567  234 
4>  11  028  137  048  139  068 
 159  024  179  026  135 
 12  046  579  246  157  248 
 357  268  359  468  379 

 0  1  2  3  4 
 5  6  7  8  9 
Way too complex for this little cotton picker from Texas to figure out . . .
Orangeman
WinD,
Thanks for sharing your ideas.
I noticed that Illinois Pick 3 Evening has the following:
Digit # Position 1 Position 2 Position 3 All Positions
2 11 32 9 9
7 33 27 12 12
8 17 8 5 5
Sums Drawings Out
0 20
5 15
6 33
wsls
Possible Boxed combinations: No Match
Combinations containing any 1 of the 3 Digits (2, 7, and 8) See Above Post
Sum 0
037 479 028 127 235 389 578
Sum 5
168 249 258 357 023 078 367 348
Sum 6
259 358 024 079 178 367 457 123
wsls
Thanks Winsum. Your very nice to help me out. I don't seem able to write out my meanings on this at all well. I would give up if it wasn't so important as a filter.
Thanks for that Ill. Eve. info ..... those 3 Sums are ripe.
Windy,
Using your short list, Tenn would be a play tonight.
sum 3 out 23 days
sum 0 out 26 days
sum 1 out 39 days
Using another filter ; play numbers that contain at least one of the digits from the last two drawn numbers
I came up with 25 singles, 17 doubles for a total of 42 numbers to play. I have posted them on the prediction page
ez
WinD I am just starting to understand this and understand the value of it.....
One question.....
Is this a positional like Position 1, Position 2 and Position3 basically the longest out in each position....
Or is it the longest out regardless of position....like that all positions WSLS had....
Okay say position 1 had a 6 out for 10 draws (it is the longest out in this position)
say position 2 had a 9 out for 15 draws (it is the longest out in position 2)
and say in Position 3 , the 2 has been out for 10 draws in this position BUT the 1 has been out for 8 draws...................what then?
Combined postion (regardless of position), the 8 has been out for 12 draws....etc...
which do we use........the 6,9,2 or the 8,x,x.....
Example # 2: Monday Eve
Mass Pick 4  Play Pick 3 using the Front 3 or Back 3 of the Pick 4 drawn.
Mass Front 3:
Digit P1 P2 P3
5 5 18 28
6 13 6 8
8 6 8 14
Sums Drawings Out
2 30
7 22
9 17
wsls
Example # 3: Monday Eve
Michigan Evening Drawing  Monday 8/15/05
Digit P1 P2 P3
3 10 6 5
6 5 7 21
8 7 15 26
Sums Drawings Out
6 20
8 17
9 25
wsls
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